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x^2+439.2x-14884=0
a = 1; b = 439.2; c = -14884;
Δ = b2-4ac
Δ = 439.22-4·1·(-14884)
Δ = 252432.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(439.2)-\sqrt{252432.64}}{2*1}=\frac{-439.2-\sqrt{252432.64}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(439.2)+\sqrt{252432.64}}{2*1}=\frac{-439.2+\sqrt{252432.64}}{2} $
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